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a project worth $800

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a project worth $800

by sanju09 » Thu Apr 02, 2009 3:36 am
A is twice as efficient as B, and C is 50 percent more efficient than A. The three work together on a project worth $800, and would share the sum in proportion to the part of task they contribute. What sum will C receive when the task is done?
A. $200
B. $250
C. $300
D. $350
E. $400
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by scoobydooby » Thu Apr 02, 2009 3:57 am
let A do 2W part of the work
B does W part of the work
C does 3W part of the work
=> Cs proportion of contribution: 3W/6W=1/2
so C will receive 1/2*800=$400

hence E
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by vittalgmat » Thu Apr 02, 2009 1:51 pm
Tricky language!.. I got a few questions while reading the Q.
"C is 50% more efficient than A"
I think it means C is 1.5 times efficient than A.

Pls correct me if I am wrong.

thanks
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by gmat740 » Thu Apr 02, 2009 4:49 pm
@vittal

You are correct

Actually its better to proceed by assuming value of B rather that of A because A is expressed in terms of B as Twice of B

So,

B= W

A =2W

And C= 1.5 of A

C= 1.5 *(2W)

C= 3W


total = 800 =2W+W+3W

W= 800/6

C's share = 3*W
= 3*800/6

=400
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by quocbao » Fri Apr 03, 2009 1:20 am
Is it better ?

Let assume A is 100

=> B = 50, C = 150

The ratio will be

A : B : C = 100 : 50 : 150 = 2 : 1 : 3

Or C equal to 3 / (2 + 1 + 3) = 1/2 total

=> C get 1/2 money = 1/2 800 = 400
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by gmat740 » Fri Apr 03, 2009 6:43 am
@Quocbao
it completely depends upon how you perceive a given problem.

Choose which ever way you feel like, after all, it is the answer which matters :D
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