If the sequence x1, x2, x3, …, xn, … is such that x1 = 3 and xn+1 = 2xn – 1 for n ≥ 1, then x20 – x19 =
A. 2^19
B. 2^20
C. 2^20 - 1
E. 2^21 - 1
OA: A
A. 2^19
B. 2^20
C. 2^20 - 1
E. 2^21 - 1
OA: A
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In sequence questions, it's a very good idea to write down the first few terms, to see if a pattern emerges:ketkoag wrote:If the sequence x1, x2, x3, …, xn, … is such that x1 = 3 and xn+1 = 2xn – 1 for n ≥ 1, then x20 – x19 =
A. 2^19
B. 2^20
C. 2^20 - 1
E. 2^21 - 1
OA: A
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