The answer should be 4.baller12q wrote:If the aveage of the 4 numbers n+2, 2n-3, 4n+1, and 7n+4 is 15 what is the value of N
((n+2)+(2n-3)+(4n+1)+(7n+4))/4 = 15
(n+2)+(2n-3)+(4n+1)+(7n+4) = 60
14n = 60-4
n= 56/14 = 4
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problem solving
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((n+2)+(2n-3)+(4n+1)+(7n+4))/4 = 15
(n+2)+(2n-3)+(4n+1)+(7n+4) = 60
14n = 60-4
n= 56/14 = 4
