BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

cards

Expert replies
Source: — Problem Solving |

by krisraam » Wed Mar 25, 2009 7:21 pm
Finding the probability of selecting cards that are not pairs.

Probability of selecting first card = 12/12 = 1 ( It can be any card).

Probability of selecting second card = 10/11 ( 11 cards are left for selection. We shouldn't select the matching card. )

Probability of selecting the third card = 8/10 ( 10 cards left we shouldn't select the two cards that match the already selected 2 cards)

Probability of selecting the 4th card = 6/9

Probability of selecting the cards with no pairs = 1* 10/11*8/10*6/9 = 16/33

Probability of selecting at least one pair = 1-16/33 = 17/33.

Thanks
Raama
Join the discussion

by vittalgmat » Thu Mar 26, 2009 12:16 am
On an slightly related topic. (sorry to post here. I will mail eric and mozilla guys about this issue)
Does everyone see jpg attachments properly in firefox for windows. The community sponsors banner drops down over the picture and I cant read completely.

thanks
-V
Join the discussion

by orel » Thu Mar 26, 2009 12:52 am
Vittal,

the same happens to me. I cannot properly see the attachments on posts. :(
Join the discussion

by avenus » Thu Mar 26, 2009 1:47 am
On an slightly related topic. Does everyone see jpg attachments properly in firefox for windows. The community sponsors banner drops down over the picture and I cant read completely. thanks -V
A quick solution: place the mouse pointer over the image, click on the right button and select show image or the equivalent in the language/browser you're using. The image on its own will be shown in a separate tab...
Join the discussion

by kanha81 » Thu Mar 26, 2009 9:15 am
krisraam wrote:Finding the probability of selecting cards that are not pairs.

Probability of selecting first card = 12/12 = 1 ( It can be any card).

Probability of selecting second card = 10/11 ( 11 cards are left for selection. We shouldn't select the matching card. )

Probability of selecting the third card = 8/10 ( 10 cards left we shouldn't select the two cards that match the already selected 2 cards)

Probability of selecting the 4th card = 6/9

Probability of selecting the cards with no pairs = 1* 10/11*8/10*6/9 = 16/33

Probability of selecting at least one pair = 1-16/33 = 17/33.

Thanks
Raama
I really like the way you solve the problems, makes it look simpler and understandable. I always fight between 2 methods. This is the method that I chose; however, it took more than 2 mins, but less than 4 mins.

P(E): Finding at least 1 pair that have same value.
4 cards chosen from 12: 12C4 ways

We find P(E`): Finding none of the 4 cards chosen have same value
=6C4 * 4C1 * 4 (ie choose 4 cards from a pair of 6 cards, such that, you choose 1 card from each pair and this can be done in 4 ways) / (12C4)

= 16/33

p(E) = 1-P(E`) = 1 - 16/33 = 17/33
Want to Beat GMAT.
Always do what you're afraid to do. Whoooop GMAT
Join the discussion

by vittalgmat » Thu Mar 26, 2009 2:42 pm
avenus wrote:
On an slightly related topic. Does everyone see jpg attachments properly in firefox for windows. The community sponsors banner drops down over the picture and I cant read completely. thanks -V
A quick solution: place the mouse pointer over the image, click on the right button and select show image or the equivalent in the language/browser you're using. The image on its own will be shown in a separate tab...
Thanks avenus. As u mentioned, I right clicked on the Ad and chose "block images". This blocked images from page2ad.google.com.
Join the discussion

by RBurroughs » Thu Mar 26, 2009 8:05 pm
vittalgmat wrote:On an slightly related topic. (sorry to post here. I will mail eric and mozilla guys about this issue)
Does everyone see jpg attachments properly in firefox for windows. The community sponsors banner drops down over the picture and I cant read completely.

thanks
-V
you can also right click and select "do not show images from this site" to block advertisements
Join the discussion

by Vemuri » Fri Mar 27, 2009 5:48 am
krisraam wrote:Finding the probability of selecting cards that are not pairs.

Probability of selecting first card = 12/12 = 1 ( It can be any card).

Probability of selecting second card = 10/11 ( 11 cards are left for selection. We shouldn't select the matching card. )

Probability of selecting the third card = 8/10 ( 10 cards left we shouldn't select the two cards that match the already selected 2 cards)

Probability of selecting the 4th card = 6/9

Probability of selecting the cards with no pairs = 1* 10/11*8/10*6/9 = 16/33

Probability of selecting at least one pair = 1-16/33 = 17/33.

Thanks
Raama
I am confused here....appreciate some help clearing out the cloud for me. Thanks in advance.

When I look at the way the question is framed, I am considering that 4 cards have been laid out & we have 8 cards remaining to find the probability of not finding a match. Can someone please help with explaining the approach.
-------------------------------------------------
Earth Hour 2009
Vote Earth! Your light switch is your vote.
https://www.earthhour.org/home/
Join the discussion

by rs2010 » Fri Mar 27, 2009 9:08 am
vittalgmat wrote:On an slightly related topic. (sorry to post here. I will mail eric and mozilla guys about this issue)
Does everyone see jpg attachments properly in firefox for windows. The community sponsors banner drops down over the picture and I cant read completely.

thanks
-V
Safari, Chrome and Firefox also. Think about Mac OS, which does not have IE.

Work around: to view properly right click on image and view it in another tab.

I feel its more with formatting than with browsers.
Join the discussion