sudhir3127 wrote:sudhir3127 wrote:A boats crew consists of 8 men . 3 of whom can only row on one side and 2 only on the other, Find the number of ways in which the crew can be arranged...
Answers after few discussions.
here are the Answer choices
a.8!/6!*5!
b.8!/2!3!
c.3(4!)*(4!)
d.4!/3!*2!
What is the 5th option?
My answer is 9 * 4! * 4!
Explanation:
There are 8 men say A B C D E F G H
On 1 side 2 men has to be seated along with 2 other (from the pool of 3 men who can row both sides)
Let A & B be 2 men who can row on 1 side
Let F, G & H be 3 men who can row on the second side
and let C, D n E be 3 men who can row both sides
so the anagram is for 1 side is (with 2 men on one side)
1 2 3 4
A B C D - 4! ways can be seated
A B C E - 4! ways can be seated
A B D E - 4! ways can be seated
so for 1 side 3*4!
Let's look at the anagram for the second side:
so the anagram is for 2 side is (with 3 men on one side)
5 6 7 8
F G H E - 4! ways can be seated
F G H D - 4! ways can be seated
F G H C - 4! ways can be seated
so for 2 side 3*4!
In all there are 1 side * 2 side arrangements so 3 * 4! * 3 * 4! = 9 * 4! * 4!
I am not sure if this approach is correct. What's the OA?