Hi,
Can you please explain how do we het 25? I read the explanation from MGMAT. But could not understand that. They are mentioning following.
Would you please explain why we are doing 5*5 ? Means would we not be having some repeations if we do that?
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36^2 can be expressed as the product of its prime factors, raised to the appropriate exponents:
362 = (22 × 32)2 = 24 × 34
So, the prime box of 362 contains four 2's and four 3's, as shown:
2 2 2 2 3 3 3 3
Now, if you pick any combination of these primes and multiply them all together, the product will be a factor of 362. As you take primes from this prime box to construct a factor of 362, note that you can choose up to four 2's and up to four 3's. In fact, you have FIVE choices for the number of 2's you put into the factor: zero, one, two, three, or four 2's. Likewise, you have the same FIVE choices for the number of 3's you put into the factor: zero, one, two, three, or four. (It doesn't matter what order you pick the factors, since order doesn't matter in multiplication.)
Note that you are allowed to pick zero 2's and zero 3's at the same time. By doing so, you are constructing the factor 20 × 30 = 1, which is a separate, valid factor of 362.
Since you have five independent choices for the number of 2's you pick AND you have five independent choices for the number of 3's you pick, you MULTIPLY the number of choices together to get the number of options you have overall. Thus you have 5 × 5 = 25 different ways to construct a factor. This means that there are 25 different factors of 362.
The correct answer is D.
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Thanks in advance.
[
quote="P_mashru"]Dear thegmatbeater!
You might have taken this question from MGMAT. The correct question ask no of fectors of 36^2 and not 36.
Pl confirm and I will explain why correct answer is 25[/quote]
