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by sanju09 » Wed Apr 06, 2011 12:47 am
Sheila, Janice, and Karen, working together at the same rate, can complete a job in 10/3 days. Working at the same rate, how much of the job could Janice and Karen do in one day?
A. 1/9
B. 1/8
C. 1/5
D. 1/4
E. 1/3



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by manpsingh87 » Wed Apr 06, 2011 12:56 am
sanju09 wrote:Sheila, Janice, and Karen, working together at the same rate, can complete a job in 10/3 days. Working at the same rate, how much of the job could Janice and Karen do in one day?
A. 1/9
B. 1/8
C. 1/5
D. 1/4
E. 1/3



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1/x+1/x+1/x=3/10;
therefore x=10;
now janice and karen's i day work will be 1/10+1/10=2/10=1/5 hence C
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by GMATGuruNY » Wed Apr 06, 2011 1:42 am
sanju09 wrote:Sheila, Janice, and Karen, working together at the same rate, can complete a job in 10/3 days. Working at the same rate, how much of the job could Janice and Karen do in one day?
A. 1/9
B. 1/8
C. 1/5
D. 1/4
E. 1/3



https://www.testprepreview.com
Let job = 10 units.
Combined rate for S+J+K = w/t = 10/(10/3) = 3 unite per day.
Rate for J+K alone = 2 units per day.
Fraction of job completed in 1 day = 2/10 = 1/5.

The correct answer is C.
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