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Percentage Help

by HarvardDreamin » Thu Mar 20, 2008 2:00 pm
Of the families in City X in 1994, 40 percent owned a personal computer. The number of families in City X owning a computer in 1998 was 30 percent greater than it was in 1994, and the total number of families in City X was 4 percent greater in 1998 than it was in 1994. what percent of the families in City X owned a personal computer in 1998?

A. 50%
B. 52%
C. 56%
D. 70%
E. 74%
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by xilef » Thu Mar 20, 2008 2:26 pm
Lets approach this with nice numbers:

Of the families in City X in 1994, 40 percent owned a personal computer:

lets say there are a total of 100 families and 40 of them own a computer.

in 1998 that num was 30 percent greater than it was in 1994, or 130% of 40
1.3*40=52


total number of families in City X was 4 percent greater in 1998 than it was in 1994 or 104% of our 100 families = 104 families

52 of those owned a computer which is 50% Answer A
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by HarvardDreamin » Fri Mar 21, 2008 11:51 am
Many thanks
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by bhumika.k.shah » Fri Jan 22, 2010 1:00 pm
yup ! thats how i got it :-D

Just a thought - could there be any other approach whatsoever???
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by linkinpark » Fri Jan 22, 2010 9:28 pm
bhumika.k.shah wrote:yup ! thats how i got it :-D

Just a thought - could there be any other approach whatsoever???
usually putting numbers is an easier approach in these kind of problems but I've one more

say X was population in '94 and Y in '98

so in '94 people having PC = 40/100*x = 0.4x

in '98 population was 4% greater than that in '94 so Y = X + 4/100*x = 1.04X

and in '98 number of PC owners was 30% greater than that in '94 which will be .40X + 30/100(.40*x) = .40X + .12X = .52x

now % of PC owners in '98 in terms of population in '98 = [.52X/1.04 x] * 100 = 1/2 * 100 = 50%
530->480->580
when posting a question don't post OA(even masked) before some discussion.
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by Concordio » Sat Jan 23, 2010 8:18 pm
xilef wrote:Lets approach this with nice numbers:

Of the families in City X in 1994, 40 percent owned a personal computer:

lets say there are a total of 100 families and 40 of them own a computer.

in 1998 that num was 30 percent greater than it was in 1994, or 130% of 40
1.3*40=52


total number of families in City X was 4 percent greater in 1998 than it was in 1994 or 104% of our 100 families = 104 families

52 of those owned a computer which is 50% Answer A
That's how I did it and is the easiest way I could think of.
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