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buzzdeepak
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For a certain set of numbers, if x is in the set, then x-3 is also in the set. If the number 1 is in the set, which of the following must also be in the set.
I. 4
II. -1
III.-5
A. I only
B. II only
C. III only
D. I and II only
E. II and III only
OA: C
Question:
[spoiler]If we consider x = 1, I understand -2, -5, -8 etc will be in the set.
But why can't we consider x-3 = 1, in which case 4 is a possibility as well?
So, the set would then have {..., -8, -5, -2, 1, 4}[/spoiler]
Please help
Thanks in advance...
I. 4
II. -1
III.-5
A. I only
B. II only
C. III only
D. I and II only
E. II and III only
OA: C
Question:
[spoiler]If we consider x = 1, I understand -2, -5, -8 etc will be in the set.
But why can't we consider x-3 = 1, in which case 4 is a possibility as well?
So, the set would then have {..., -8, -5, -2, 1, 4}[/spoiler]
Please help
Thanks in advance...


















