GMAT Prep Practice - Set containing x and x-3

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For a certain set of numbers, if x is in the set, then x-3 is also in the set. If the number 1 is in the set, which of the following must also be in the set.
I. 4
II. -1
III.-5

A. I only
B. II only
C. III only
D. I and II only
E. II and III only

OA: C

Question:
[spoiler]If we consider x = 1, I understand -2, -5, -8 etc will be in the set.
But why can't we consider x-3 = 1, in which case 4 is a possibility as well?
So, the set would then have {..., -8, -5, -2, 1, 4}[/spoiler]

Please help
Thanks in advance...
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by ceilidh.erickson » Wed Feb 13, 2013 8:11 am
This is one of those relatively rare times in Quant that the GMAT actually tries to trick you semantically. Just because they say "if x is in the set, then x - 3 is also in the set," it doesn't necessarily mean that "if x - 3 is in the set, x is in the set." What if x = 1? We'd be able to prove that every number 3 less than x, and 3 less than that, and so on, is in the set. But can we prove that anything greater than x is in the set? Not necessarily.

It's certainly possible that 4 is in the set. Maybe x = 4, and then 1 is x - 3. Or maybe x = 13, and 4 is x - 3 - 3 - 3. But with these Roman numeral questions, make sure you distinguish between what's possible and what's necessary. If we know a certain number is in the set, we know about the values less than that number, but not necessarily the values greater than that number.
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by Brent@GMATPrepNow » Wed Feb 13, 2013 8:25 am
It's not uncommon for people to reverse the order of if-then statements.

The if-then statement here is "If if x is in the set, then x-3 is also in the set"
Reversing the statement (to get "if x-3 is in the set, then x is also in the set") is not logically sound.

Here's an example why.

Let's say: If an animal is a rabbit, then that animal has ears.
Can we then conclude that if an animal has ears then that animal is a rabbit? No.

So, in our question, the existence of x in the set guarantees the existence of x-3 in the set.
However, it is not necessarily the case that the existence of x-3 in the set guarantees the existence of x in the set.

I hope that helps.

Cheers,
Brent
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by buzzdeepak » Wed Feb 13, 2013 8:34 am
Thanks for the detailed explanations, Ceilidh and Brent.

The approach to problems such as these is clear now :)