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Chinn_asama
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x = y^aChinn_asama wrote:If x=y^a, y=z^b and z= x^c, then abc=?
y = z^b --> z = y^(1/b)
z = x^c = (y^a)^c = y^(ac)
So, y^(1/b) = y^(ac)
--> 1/b = ac
--> abc = 1
