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by ramonsa » Wed Jun 03, 2009 1:28 pm
19. If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
(A) 86
(B) 52
(C) 34
(D) 28
(E) 10
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Source: — Data Sufficiency |
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by SanjeevK » Wed Jun 03, 2009 2:32 pm
M can be written as 6a + 1
N can be written as 6b + 3

M+N = 6(a+b) + 4

Only option A 2 as remainder when divided by 6. Rest leaves 4
IMO A
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