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PS - Help needed solving problem

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Re: PS - Help needed solving problem

by ashishjha100 » Sun Sep 07, 2008 8:52 am
madsport wrote:Please help

The answer is D
[3x^2(x-2)-(x-2)]/[x-2]

cancelling x-2 in common

(3x^2 - 1) is what remaining...... :idea:
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by madsport » Sun Sep 07, 2008 9:21 am
[3x^2(x-2)-(x+2)]/[x-2]


the question and an addition sign in the numerator. See above. This changes the method used to solve the problem.
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by ashishjha100 » Sun Sep 07, 2008 4:17 pm
madsport wrote:[3x^2(x-2)-(x+2)]/[x-2]


the question and an addition sign in the numerator. See above. This changes the method used to solve the problem.

[3x^2(x-2)-(x+2)]/[x-2]


The highlighted -ve sign is taken as common for x and 2.so inside the sign will go +ve not -ve as i highlighted.
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