[3x^2(x-2)-(x-2)]/[x-2]madsport wrote:Please help
The answer is D
cancelling x-2 in common
(3x^2 - 1) is what remaining......
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PS - Help needed solving problem
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cancelling x-2 in common
(3x^2 - 1) is what remaining......
[3x^2(x-2)-(x+2)]/[x-2]
the question and an addition sign in the numerator. See above. This changes the method used to solve the problem.
the question and an addition sign in the numerator. See above. This changes the method used to solve the problem.
madsport wrote:[3x^2(x-2)-(x+2)]/[x-2]
the question and an addition sign in the numerator. See above. This changes the method used to solve the problem.
[3x^2(x-2)-(x+2)]/[x-2]
The highlighted -ve sign is taken as common for x and 2.so inside the sign will go +ve not -ve as i highlighted.
