Rectangle

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odod: Senior | Next Rank: 100 Posts; Posts: 56; Joined: Tue Jan 13, 2009 12:59 pm; Location: Toronto; Thanked: 1 times

by odod » Wed Apr 01, 2009 11:05 am

Hello,

Please see the attachment and advise if you can figure out how to solve it.

Thanks.

OA - A

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ODOD

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Source: Beat The GMAT — Problem Solving | Wed Apr 01, 2009 11:05 am

relic: Junior | Next Rank: 30 Posts; Posts: 22; Joined: Tue Mar 31, 2009 5:28 am; Thanked: 3 times; GMAT Score:780

by relic » Wed Apr 01, 2009 11:14 am

If the sides of the rectangle are y and z, then the area of the shaded region will be the area of the rectangle minus the area of the unshaded triangle,

5x^2 = yz - 0.5*x*2x = yz - x^2

solve for the area of the rectangle, yz

yz = 6x^2

The answers represent potential sides of the rectangle, so we seek the answer whose product is 6x^2. Only answer A gives such a result.

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HumbleMe: Junior | Next Rank: 30 Posts; Posts: 20; Joined: Wed Apr 01, 2009 1:04 pm; Location: Toronto, Canada; Thanked: 1 times; GMAT Score:710

by HumbleMe » Wed Apr 01, 2009 1:11 pm

Area of unshaded area is = (2x*x)/2 = x^2
Total area of rectangle = 5x^2 + x^2 = 6x^2

Out of given option, only A makes sure that area is 6 x^2. Hence A

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