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Source: — Problem Solving |
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by GMATinsight » Sat Jul 19, 2014 4:09 am
[email protected] wrote:Hello experts,


What does it mean by increment number in this problem?

Pls explain
Since A,B,C,D and E are evenly spaced therefore
B-A = C-B = D-C = E-D

Since, Distance between E and C = 2 Spaces, therefore,

Every Space between any two consecutive Letters = (E-C)/2 = (9^13 - 9^11)/2

Every Space between any two consecutive Letters = (9^11)(9^2 - 1)/2
Every Space between any two consecutive Letters = (9^11)(80)/2 = 40 x (9^11)

Distance between A to D = 3 Spaces
i.e. Distance between A to D = 3 x 40 x (9^11) = 120 x (9^11)

Answer: Option E
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by GMATGuruNY » Sat Jul 19, 2014 7:15 am
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In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)
There are 3 spaces between A and D.
There are 2 spaces between C and E.
Thus:
AD/CE = 3/2
AD = (3/2)(CE).

CE = 9¹³ - 9¹¹ = (9¹¹)(9² - 1) = (9¹¹)(80).

Thus:
AD = (3/2)(CE) = (3/2)(9¹¹)(80) = (120)(9¹¹).

The correct answer is E.
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by Brent@GMATPrepNow » Sat Jul 19, 2014 9:28 am
Here's a similar question to practice with: https://www.beatthegmat.com/challenge-2- ... 67201.html

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by Jeff@TargetTestPrep » Thu Dec 14, 2017 3:39 pm
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In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)
We can let the space between each pair of consecutive points = n.

Thus, the space from C to E is n + n = 2n. So, we can create the following equation:

9^11 + 2n = 9^13

2n = 9^13 - 9^11

2n = 9^11(9^2 - 1)

2n = 9^11(80)

n = 9^11(40)

Since the distance from A to D = 3n:

3n = 3(9^11)(40) = 120(9^11)

Answer: E

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