each term is obtained by adding 4 to the preceding one

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by kajcha » Tue Sep 18, 2007 5:21 pm
Ans C

This is AP. Sum of n terms in AP is given by

S(n) = n/2(2a+(n-1)d)

First part of q says

80 = 10/2(2a+(10-1)4) => a = -10

Now S(40) = 20(2*-10+(40-1)4) = 2720

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by dpatwa » Tue Sep 18, 2007 10:37 pm
Where is S(n) = n/2(2a+(n-1)d) from? what property is it?

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by kajcha » Wed Sep 19, 2007 3:00 am