BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

PR Question

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Master | Next Rank: 500 Posts
Posts: 400
Joined: Sat Mar 10, 2007 4:04 am
Thanked: 1 times
Followed by:1 members

PR Question

by f2001290 » Mon May 07, 2007 6:27 am
Please Explain the attached question.

How can we determine that a right angles triangle has the maximim area.
Attachments
PRQues.JPG
Top
Source: — Problem Solving |
User avatar
Community Manager
Posts: 789
Joined: Sun Jan 28, 2007 3:51 pm
Location: Silicon valley, California
Thanked: 30 times
Followed by:1 members

Re: PR Question

by jayhawk2001 » Mon May 07, 2007 6:05 pm
f2001290 wrote:Please Explain the attached question.

How can we determine that a right angles triangle has the maximim area.
Hmm, not sure how we can explain this without involving trigonometry

If triangle has sides a and b and x is the angle between the 2 sides,
the area is given by

A = 1/2*ab*sin(x)

Now, area is maximum when sin(x) is max. sin(x) is max when x = 90
degress.

So, it has to be a right angle triangle.

So, 3rd side is sqrt(25+64) = sqrt(89)
Top
Post new topic Post Reply
• Page 1 of 1