Total # of pairs = (4*3) / 2 = 6grandh01 wrote:How many two-element subsets of {1,
2, 3, 4} are there that do not contain
the pair of elements 2 and 4?
(A) One
(B) Two
(C) Four
(D) Five
(E) Six
No. of pair of 2 and 4 = 1
No of pair that do not contain 2 and 4 = 6 - 1 = 5
ans = d













