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Problem 2

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Problem 2

by anwarma » Tue Jun 10, 2008 9:05 am
A 4 person task force is to be formed from the 4 men and 3 women who work in a COMPANY G' HR dept. If there are to be 2 men and 2 women on this task force , how many different task forces can be formed?

(A) 14
(B) 18 <<--ANSWER
(C) 35
(D) 56
(E) 144

I am not sure how answer is 18.
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by egybs » Tue Jun 10, 2008 9:15 am
We need to choose 2 men out of 4 men and 2 women out of 3 women. So we have the following combination that needs to occur:

4C2 * 3C2 = 18

Check out this excellent article on Permutations and Combinations:
https://www.mansw.nsw.edu.au/members/ref ... no4yen.htm
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by rosh26 » Tue Jun 10, 2008 4:26 pm
Hi Can you do the mathamatical computation to this answer?

Or even factorials would work...thanks...
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by egybs » Tue Jun 10, 2008 4:42 pm
sure -

4C2 = 4!/(2!*(4-2)!) = 24/4 = 6

3C2 = 3!/(2!*(3-2)!) = 6/2 = 3

6*3=18
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by amirp » Wed Aug 11, 2010 2:53 pm
it seems like we ignore the part that says "A 4-person task force is to be formed..." . would the answer be the same if the question asked for "A 5-person task force is to be formed ... "?

can anyone clarify this?
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by ketandoshi » Wed Aug 11, 2010 6:32 pm
Amirp,

We are not neglecting "4 -person" as the task force has 2 men and 2 women (4C2* 3C2) if you had "5 -person" then it may ask as 3 men & 2 women or 2 men & 3 women. If I am wrong please somebody correct me.
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by amirp » Wed Aug 11, 2010 7:46 pm
ohhhh, I see. you are correct. We are considering it, but in an indirect way.

thanks
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by likithae » Wed Aug 11, 2010 11:20 pm
ketandoshi wrote:Amirp,

We are not neglecting "4 -person" as the task force has 2 men and 2 women (4C2* 3C2) if you had "5 -person" then it may ask as 3 men & 2 women or 2 men & 3 women. If I am wrong please somebody correct me.

yes..... you are correct.......
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