The earlier explanation is dead on. Just to supply the algebra, I'll add a little bit.
Before going to the two statements, try to extract as much as you can from the question stem. We know:
v² ≥ 0 for any value of v (on the GMAT)
t-� = 1/t� = (1/t²)², and as above, anything squared ≥ 0, so (1/t²)² ≥ 0 for any value of t
Since the stem tells us v*m*t ≠0, we know v ≠0 and t ≠0, so v² > 0 and (1/t²)² > 0.
That means the only think we need to know is whether m is positive or negative: the result of a base raised to an odd power has the same sign as its base. (In other words, if m < 0, m³ < 0, and if m > 0, m³ > 0.) This means we can rephrase the question as "Is m positive?"
S1:: m > v², and v² > 0, so m > 0, SUFFICIENT.
S2:: m > 1/t� and 1/t� > 0, so m > 0, SUFFICIENT.