Properties of numbers Quant Review 2nd Ed #172

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by GMATGuruNY » Fri Sep 20, 2013 2:27 pm
runningguy wrote:If x, y, and z are positive integers such that x is a factor of y, and x is a multiple of z, which of the following is NOT necessarily an integer?

A) x+z/z
B) y+z/x
C) x+y/z
D) xy/z
E) yz/x
Let y=20.
Since x is a factor of y, let x=10.
Since x is a multiple of z, let z=5.

A: (x+z)/z = (10+5)/5 = 3.
B: (y+z)/x = (20+5)/10 = 2.5.

B is not necessarily an integer.
No need to check the remaining answer choices.

The correct answer is B.
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by Brent@GMATPrepNow » Fri Sep 20, 2013 2:42 pm
runningguy wrote:If x, y, and z are positive integers such that x is a factor of y, and x is a multiple of z, which of the following is NOT necessarily an integer?

A) (x+z)/z
B) (y+z)/x
C) (x+y)/z
D) (xy)/z
E) (yz)/x
Note: To avoid confusion, I added some brackets to your answer choice.
Mitch already showed the approach of looking for values of x, y and z, such that we get a non-integer.

Here's another approach:

x is a multiple of z
So, we can say that x = kz (for some integer k)

x is a factor of y
In other words, y is a multiple of x.
So, we can say that y = jx (for some integer j)
IMPORTANT: Since we already know that x = kz, let's replace x with kz to get: y = jkz

So, x = kz, y = jkz and z = z.
Let's plug in these values to see what we get:

A) (x+z)/z = (kz+z)/z = k+1 (= INTEGER)
B) (y+z)/x = (jkz+z)/kz = (jk+1)/k (not necessarily an integer)
C) (x+y)/z = (kz+jkz)/z = k+jk (= INTEGER)
D) (xy)/z = [(kz)(jkz)]/z = jk²z (= INTEGER)
E) (yz)/x = [(jkz)(z)]/kz = jz (= INTEGER)

Answer = B

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by theCodeToGMAT » Sat Sep 21, 2013 5:32 am
X * _ = y
Z * _ = x
Let,
z=2
x=4
y=8
(A) (4+2)/2 -- INTEGER
(B) (8+2)/4 -- NOT AN INTEGER
(C) (4+8)/2 -- INTEGER
(D) 4*8/2 -- INTEGER
(E) 8*2/4 -- INTEGER

ANSWER [spoiler]{B}[/spoiler]
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