This is question 5 on the just published 2012 OG and either they made a mistake or I'm going crazy...
A closed cylindrical tank contains 36pi cubic feet of water and is filled to half its capacity. When the tank is placed upright on its circular base on level ground, the height of the water in the tank is 2 feet. When the tank is placed on its side on level ground, what is the height, in feet, of the surface of the water above ground?
So if half the volume = 36pi, then the cylinder's total volume = 72pi
And if half the height of the tank = 2, then the total height of tank = 4
Solving for the radius, 72pi = r^2(pi)(4)
18 = r^2
r = sqrt(18)
Book says the answer is 3. Only way that works is if the total height of the tank is 8. Did the snobby test makers make an error or have I lost my mind?
A closed cylindrical tank contains 36pi cubic feet of water and is filled to half its capacity. When the tank is placed upright on its circular base on level ground, the height of the water in the tank is 2 feet. When the tank is placed on its side on level ground, what is the height, in feet, of the surface of the water above ground?
So if half the volume = 36pi, then the cylinder's total volume = 72pi
And if half the height of the tank = 2, then the total height of tank = 4
Solving for the radius, 72pi = r^2(pi)(4)
18 = r^2
r = sqrt(18)
Book says the answer is 3. Only way that works is if the total height of the tank is 8. Did the snobby test makers make an error or have I lost my mind?












