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Combinatorics - GMAT PREP

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by sethids » Mon Sep 01, 2008 4:54 pm
There are 4C1 = 4 different ways of chosing an entree.
There are 5C2 = 10 different ways of chosing 2 side dishes.
Total combinations = 4 * 10 = 40
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by sushilmore » Mon Sep 01, 2008 4:54 pm
Ans - 40

one entree is selected in 4C1 ways i.e 4 ways
2 side dishes out of 5 can be selectec in 5C2 way = 10

hence the combination = 4 X 10 = 40
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by nervesofsteel » Tue Sep 02, 2008 12:44 am
4C1 * 5C2 = 40
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by 4meonly » Wed Sep 03, 2008 8:10 am
rosh26, I think you made a mistake assuming that 1 side is needed
in that case you'll have 10 combinations
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