work/rate

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superrrom: Senior | Next Rank: 100 Posts; Posts: 39; Joined: Mon Sep 01, 2008 6:27 am; Thanked: 2 times

by superrrom » Mon Sep 01, 2008 9:23 am

Thanks

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Source: Beat The GMAT — Problem Solving | Mon Sep 01, 2008 9:23 am

sudhir3127: Legendary Member; Posts: 829; Joined: Mon Jul 07, 2008 10:09 pmFollowed by: 3 members; Location: INDIA; Thanked: 84 times

Re: work/rate

by sudhir3127 » Mon Sep 01, 2008 9:31 am

superrrom wrote:Thanks

7000B= 100000- 9000*8

7000b = 28000

hence b takes 28000/7000 hr = 4

hope that helps..

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II: Master | Next Rank: 500 Posts; Posts: 400; Joined: Mon Dec 10, 2007 1:35 pm; Location: London, UK; Thanked: 19 times; GMAT Score:680

by II » Mon Sep 01, 2008 1:54 pm

I used similar approach as Sudhir here. Just to add some more explanation ...

Question is asking to us find out the least amount of time that Machine B needs to work. We know that the maximum working time is 8 hours ... so if Machine A worked for for its maximum time: 8 hours, then it would have produced 9000*8 = 72000 pencils.
This leaves 28000 pencils to be produced (100000-72000).
From this we can work out how long machine B needs to work.

RT = W
T = W/R
T = 28000/7000
T = 4

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canuckclint: Master | Next Rank: 500 Posts; Posts: 154; Joined: Tue Aug 26, 2008 12:59 pm; Location: Canada; Thanked: 4 times

by canuckclint » Wed Sep 03, 2008 2:11 pm

You want to maximize A's production and work it for 8 hours.

9000 * 8 will produce 72,000 pencils.
72,000 + 7000 * TimeB = 100,000
TimeB = 4 hours

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