If k and n are integers, is n divisible by 7?
(1) n/2-3=k
(2) 2k-1 is divisible by 7

The OA is C. But I disagree with it. It should be A according to me

Here's why
(1) n/2-3=k

Rewritten as (n-6)/2=k
n-6=2k
n=2k+6

Now 2k and 6 are both even numbers. Even+Even=Even. Hence, n is even. If n is even then it can't be divisible by 7. Am I making sense?

(2)
2k-1 is divisible by 7
Gives no hints on the divisibility of n hence insufficient.

Answer is A

Thoughts, Comments? lol