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Atekihcan
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I won't go for plugging as there is a better method (based on similarity of triangles or can be interpreted as weighted average) which I feel is the fastest method for this problem.
Let us assume the coordinate of the point we are looking for is (x, y).
Now, x = [1*(x-coordinate of P) + 2*(x-coordinate of Q)]/(1 + 2) = [0 + 6]/3 = 2
And, y = [1*(y-coordinate of P) + 2*(y-coordinate of Q)]/(1 + 2) = [-1 + 4]/3 = 1
Answer : B
Let us assume the coordinate of the point we are looking for is (x, y).
Now, x = [1*(x-coordinate of P) + 2*(x-coordinate of Q)]/(1 + 2) = [0 + 6]/3 = 2
And, y = [1*(y-coordinate of P) + 2*(y-coordinate of Q)]/(1 + 2) = [-1 + 4]/3 = 1
Answer : B
