PS- number prop 264 600
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Source: Beat The GMAT — Problem Solving |
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praky_rules
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264600 = 2^3 x 5^2 x 3^3 x 7^2
Total number of factors that are not divisible by 6 = Total number of factors - Total number of factors divisible by 6.
Total number of factors = (3+1) x (2+1) x (3+1) x (2+1) = 144 (For 2^3 term, you can pick "2" 3 times or not pick it at all = (3+1))
Total Number of factor divisible by 6 = you have to pick 2 atleast once and 3 atleast once. So total possible factors = 3 x (2+1) x 3 x (2+1)
= 81
144-81 = 63. Can I get a hug?
Total number of factors that are not divisible by 6 = Total number of factors - Total number of factors divisible by 6.
Total number of factors = (3+1) x (2+1) x (3+1) x (2+1) = 144 (For 2^3 term, you can pick "2" 3 times or not pick it at all = (3+1))
Total Number of factor divisible by 6 = you have to pick 2 atleast once and 3 atleast once. So total possible factors = 3 x (2+1) x 3 x (2+1)
= 81
144-81 = 63. Can I get a hug?
