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Source: — Data Sufficiency |
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by shankar.ashwin » Thu Nov 10, 2011 10:29 am
Statement 1

3|x^2 - 4| = 3(x^2 -4) = 3x^2 - 12 (or) -3x^2 +12

2 unknowns here, can't find 'y'

Statement 2:

|3 - y| = 11

3-y = 11 (or) -3+y=11

y = -8 (or) y = 14. (Insuff)

Together you know from statement (1)

LHS is always positive, so 'y' can't be negative. So 'y' can only take 14. C IMO
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by rijul007 » Thu Nov 10, 2011 10:30 am
What is the value of y?

(1) 3|x^2 - 4| = y - 2

(2) |3 - y| = 11
Statement 1

y = 3|x^2 - 4| + 2

only thing we can conlude is that
y > or = 0

Insufficient

Statement 2
|3 - y| = 11

y = -8 or 14

Insufficient


Combining th e two statments
y = 14
As satement 1 tells us that y is positive


Option C is the correct option
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by mankey » Sun Nov 13, 2011 11:28 am
IMO: E.

First part, since two variables, it cant be solved alone.

For second part,

3-y=11 -> y=-8 (for y>=0)
y-3=11 -> y=14 (for y<0)

Both dont satisfy.

So E.

What is the OA?

Thanks.
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