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by JeetGulia » Mon Jul 26, 2010 3:23 pm
5. AB + CD = AAA, where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?

(A) 1

(B) 3

(C) 7

(D) 9

(E) Cannot be determined

Please help!!
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by indiantiger » Mon Jul 26, 2010 3:31 pm
Answer should be D

AB
+CD
-------
AAA

Lets say B+D = 11

A+C should be 11

A+C + 1 (from carry over) = 11

now A would be 1

1+C+1 = 11
C = 9
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by saurabhmahajan » Tue Jul 27, 2010 3:55 am
It's a two digit addition so the result cant be gretaer than 198.And from 0 to 198 only 111 is the nos which can represent AAA.

So now AB means its between 10 and 19.but 10 and 11 are not possible. so we are left with 12 to 19....
now even if we take any no from 12 to 19, CD will be between 92 to 99.So C=9
Thanks and regards,
Saurabh Mahajan

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by outreach » Tue Jul 27, 2010 4:17 am
A=1
B=6
C=9
D=5
--
A=1
B=8
C=9
D=3
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