I think the answer should be A.
1/(a-b) < b-a
Statement I
a < b
From this we get
a-b < 0
b-a > 0
Therefore 1/(a-b) is negative and b-a is positive
Sufficient.
Statement II
1 < la-bl
1 < -a+b---------I
a < b
1 < a-b-----------II
b < a
When a<b, 1/(a-b) is less than b-a
When b<a, 1/(a-b) is greater than b-a
Insufficient.
Hence A.
Whats the OA?













