URGENTLY NEED HELP!!! (Test in 1 day!!)

This topic has expert replies
Source: — Problem Solving |

User avatar
GMAT Instructor
Posts: 905
Joined: Sun Sep 12, 2010 1:38 am
Thanked: 378 times
Followed by:123 members
GMAT Score:760

by Geva@EconomistGMAT » Sun Nov 21, 2010 6:14 am
rohit_gmat wrote:Please help with this question.... the way i see it, it needs imaginary numbers (i/j) ... but as per my knwledge, this aint tested on the gmat....


Image



OA will be released soon!!!

THANKSS!!!
1) No imaginary numbers needed: since x is negative, -x becomes positive. Since the absolute value is always non-negative, the result of -x|x| is the product of two positive numbers, and the root is taken correctly.

2) However, the question is indeed confusing. Since the answer choices include x, avoid the confusion by plugging in a negative value of x, such as x=-2. If x=-2, then sqrt ( -(-2)|-2|_ = sqrt (2*2) = sqrt(4) = 2. Thus, if we plug in x=-2 into the answer choices, the right answer should equal -2: Eliminate all other answer choices which do not match this goal. Doing this helps you see that the answer is A -(-2)=2, and not D x=-2, which is the strongest trap answer.

While not necessarily faster than algebra (though it can be), plugging in and eliminating is usually the safer way to solve a question with variables in answer choices. The mistakes you are likely to make dealing with abstract algebraic concepts , you are far less likely to do when using real numbers you can wrap your head around. At the end of the day, we choose A not because we have proven that A is the right answer choices algebraically, but rather because none of the other answer choices match our goal, and we know that one answer choice in 5 must be correct: since we've eliminated four answer choices, the last one must be the correct one, and we needn't worry about why.
Last edited by Geva@EconomistGMAT on Sun Nov 21, 2010 6:19 am, edited 1 time in total.
Geva
Senior Instructor
Master GMAT
1-888-780-GMAT
https://www.mastergmat.com

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 1179
Joined: Sun Apr 11, 2010 9:07 pm
Location: Milpitas, CA
Thanked: 447 times
Followed by:88 members

by Rahul@gurome » Sun Nov 21, 2010 6:15 am
rohit_gmat wrote:Please help with this question.... the way i see it, it needs imaginary numbers (i/j) ... but as per my knwledge, this aint tested on the gmat....

If x < 0, then √(-x|x|) is
  • (A) -x
    (B) -1
    (C) 1
    (D) x
    (E) √x
Don't worry.
This doesn't need any imaginary number concept! :)

As x < 0, |x| = -x.
Thus √(-x|x|) = √[(-x)*(-x)] = √(x²) = |x| = -x

The correct answer is A.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)

User avatar
Master | Next Rank: 500 Posts
Posts: 158
Joined: Wed Jun 16, 2010 8:21 am
Thanked: 13 times
Followed by:1 members

by rohit_gmat » Sun Nov 21, 2010 6:29 am
damnnnnnnnnn... i totally didnt see that... i even plugged in n then picked "x" :P

thank u alll & plz pray for me !! :)

BTG rocks!!

User avatar
GMAT Instructor
Posts: 905
Joined: Sun Sep 12, 2010 1:38 am
Thanked: 378 times
Followed by:123 members
GMAT Score:760

by Geva@EconomistGMAT » Sun Nov 21, 2010 6:57 am
Best of luck!
Geva
Senior Instructor
Master GMAT
1-888-780-GMAT
https://www.mastergmat.com

User avatar
Master | Next Rank: 500 Posts
Posts: 158
Joined: Wed Jun 16, 2010 8:21 am
Thanked: 13 times
Followed by:1 members

by rohit_gmat » Sun Nov 21, 2010 9:31 am
Thanks !!!!


BTW OA is A

Junior | Next Rank: 30 Posts
Posts: 20
Joined: Tue Aug 03, 2010 8:37 am
Thanked: 1 times

by purnimaksingh » Tue Nov 23, 2010 12:06 pm
rohit_gmat wrote:damnnnnnnnnn... i totally didnt see that... i even plugged in n then picked "x" :P

thank u alll & plz pray for me !! :)

BTG rocks!!
One t hing I didnt unederstand mod[x]=sqrt[x] how is that

Junior | Next Rank: 30 Posts
Posts: 20
Joined: Tue Aug 03, 2010 8:37 am
Thanked: 1 times

by purnimaksingh » Tue Nov 23, 2010 12:07 pm
rohit_gmat wrote:damnnnnnnnnn... i totally didnt see that... i even plugged in n then picked "x" :P

thank u alll & plz pray for me !! :)

BTG rocks!!
One t hing I didnt unederstand mod[x]=sqrt[x] how is that

User avatar
Legendary Member
Posts: 866
Joined: Mon Aug 02, 2010 6:46 pm
Location: Gwalior, India
Thanked: 31 times

by goyalsau » Tue Nov 23, 2010 6:08 pm
purnimaksingh wrote:
One t hing I didnt unederstand mod[x]=sqrt[x] how is that
If x < 0, then √(-x|x|) is

(A) -x
(B) -1
(C) 1
(D) x
(E) √x[/list][/quote]

I think it better to solve it with assuming a value of x , I know the solution provided by Rahul is the Shortest But it is the shortest but assuming value for x will be good too,

Lets x = -2

√(-x|x|) = √(-(-2)|-2|)
√(2 * 2)
= 2

x = - 2

- x = - ( - 2 ) , - x = 2

But Root will always have two values one is +ve and other one is -ve

Why we are not considering the negative value
Saurabh Goyal
[email protected]
-------------------------


EveryBody Wants to Win But Nobody wants to prepare for Win.

Senior | Next Rank: 100 Posts
Posts: 58
Joined: Fri Oct 22, 2010 1:05 am
Location: Bhopal
Thanked: 1 times
GMAT Score:710

by mk101 » Tue Nov 23, 2010 6:26 pm
goyalsau wrote:
purnimaksingh wrote:
One t hing I didnt unederstand mod[x]=sqrt[x] how is that
If x < 0, then √(-x|x|) is

(A) -x
(B) -1
(C) 1
(D) x
(E) √x[/list]
I think it better to solve it with assuming a value of x , I know the solution provided by Rahul is the Shortest But it is the shortest but assuming value for x will be good too,

Lets x = -2

√(-x|x|) = √(-(-2)|-2|)
√(2 * 2)
= 2

x = - 2

- x = - ( - 2 ) , - x = 2

But Root will always have two values one is +ve and other one is -ve

Why we are not considering the negative value [/quote]

<b>



The answer lies in the way squareroot function is defined.

Y =SQ ROOT(x) SUCH that x and y are both positive numbers.

In our case x = x^2 (this must be positive) and the evaluation , i.e. "y" is positive as well. </b>

User avatar
Legendary Member
Posts: 866
Joined: Mon Aug 02, 2010 6:46 pm
Location: Gwalior, India
Thanked: 31 times

by goyalsau » Tue Nov 23, 2010 6:36 pm
I know it may sound stupid , But i am not able to understand a word of it, Please explain it in simple language..... :(
Saurabh Goyal
[email protected]
-------------------------


EveryBody Wants to Win But Nobody wants to prepare for Win.

Senior | Next Rank: 100 Posts
Posts: 58
Joined: Fri Oct 22, 2010 1:05 am
Location: Bhopal
Thanked: 1 times
GMAT Score:710

by mk101 » Tue Nov 23, 2010 6:47 pm
any relation of the form y = squareroot(x) is called as a square root function.....Any function is a relation between two variables. in this case the two variables are x and y.

In our case we have y = squareroot of (x^2).

The basic definition of the squareroot function says - "the function is defined only for positive values of x^2 and y".

Hence whenever we take the squareroot of a function of the form y = squareroot (x^2) , we need to consider only the positive square root of x ^2.

I hope that explains your query.

User avatar
Legendary Member
Posts: 866
Joined: Mon Aug 02, 2010 6:46 pm
Location: Gwalior, India
Thanked: 31 times

by goyalsau » Tue Nov 23, 2010 6:54 pm
mk101 wrote:any relation of the form y = squareroot(x) is called as a square root function.....Any function is a relation between two variables. in this case the two variables are x and y.

In our case we have y = squareroot of (x^2).

The basic definition of the squareroot function says - "the function is defined only for positive values of x^2 and y".

Hence whenever we take the squareroot of a function of the form y = squareroot (x^2) , we need to consider only the positive square root of x ^2.

I hope that explains your query.
Many Thanks,
I didn't know that, But as you its only for variables , Where y = square root of x ^ 2
Saurabh Goyal
[email protected]
-------------------------


EveryBody Wants to Win But Nobody wants to prepare for Win.