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baller12q: Senior | Next Rank: 100 Posts; Posts: 44; Joined: Sat Mar 28, 2009 11:28 am

by baller12q » Sat Mar 28, 2009 12:22 pm

If the aveage of the 4 numbers n+2, 2n-3, 4n+1, and 7n+4 is 15 what is the value of N

Source: Beat The GMAT — Problem Solving | Sat Mar 28, 2009 12:22 pm

schowdhary: Junior | Next Rank: 30 Posts; Posts: 11; Joined: Fri Mar 27, 2009 8:19 pm

by schowdhary » Sat Mar 28, 2009 1:10 pm

baller12q wrote:If the aveage of the 4 numbers n+2, 2n-3, 4n+1, and 7n+4 is 15 what is the value of N

The answer should be 4.

((n+2)+(2n-3)+(4n+1)+(7n+4))/4 = 15

(n+2)+(2n-3)+(4n+1)+(7n+4) = 60

14n = 60-4

n= 56/14 = 4

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