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Source: — Problem Solving |

by Brent@GMATPrepNow » Fri Sep 15, 2017 10:13 am
vaibhav101 wrote:Find the greatest number that will divide 43,91 and 183 so as to leave the same remainder in each case :
A 4
B 7
C 9
D 13
E 41
This question lends itself to testing the answer choices
Since we're looking for the greatest number, we'll start at E and work our way to A

E) 41
43 divided by 41 equals 1 with remainder 2
91 divided by 41 equals 2 with remainder 9
We need the SAME remainder each time - ELIMINATE E

D) 13
43 divided by 13 equals 3 with remainder 4
91 divided by 13 equals 7 with remainder 0
We need the SAME remainder each time - ELIMINATE D

C) 9
43 divided by 9 equals 4 with remainder 7
91 divided by 9 equals 10 with remainder 1
We need the SAME remainder each time - ELIMINATE C

B) 7
43 divided by 7 equals 6 with remainder 1
91 divided by 7 equals 13 with remainder 0
We need the SAME remainder each time - ELIMINATE B

By the process of elimination, the correct answer is A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by regor60 » Fri Sep 15, 2017 10:39 am
The key is recognizing that the only other way is a laborious one...ask me how I know
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