∛x= = x^(1/3).Hmna wrote:If x>0 satisfying (∛x)/x = x^w then what will be the value of w
A) 2/3
B)-2/3
C)-3/2
D)3/2
Thus:
(∛x)/x = x^w
[x^(1/3)]/x¹ = x^w
x^(1/3 - 1) = x^w
x^(-2/3) = x^w.
-2/3 = w.
The correct answer is B.
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∛x= = x^(1/3).Hmna wrote:If x>0 satisfying (∛x)/x = x^w then what will be the value of w
A) 2/3
B)-2/3
C)-3/2
D)3/2
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