∛x= = x^(1/3).Hmna wrote:If x>0 satisfying (∛x)/x = x^w then what will be the value of w
A) 2/3
B)-2/3
C)-3/2
D)3/2
Thus:
(∛x)/x = x^w
[x^(1/3)]/x¹ = x^w
x^(1/3 - 1) = x^w
x^(-2/3) = x^w.
-2/3 = w.
The correct answer is B.
Help plz!!
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I believe that the problem should read as follows:
Thus:
(∛x)/x = x^w
[x^(1/3)]/x¹ = x^w
x^(1/3 - 1) = x^w
x^(-2/3) = x^w.
-2/3 = w.
The correct answer is B.
Thus:
(∛x)/x = x^w
[x^(1/3)]/x¹ = x^w
x^(1/3 - 1) = x^w
x^(-2/3) = x^w.
-2/3 = w.
The correct answer is B.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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