BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

pigs and cows in a farm

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 137
Joined: Fri Nov 13, 2015 11:01 amFollowed by: 2 members
Thanked: 1 times
by Amrabdelnaby » Fri Jan 01, 2016 7:06 am
Of the 60 animals in the farm, 2/3 of the animals are either cows or pigs. How many of the animals are cows?

1) the farm has more than twice as many cows as it has big

2) the farm has more than 12 pigs

Pls explain
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 2663
Joined: Wed Jan 14, 2015 8:25 amFollowed by: 128 members
Location: Boston, MA
Thanked: 1153 times
GMAT Score:770

by DavidG@VeritasPrep » Fri Jan 01, 2016 7:16 am
Amrabdelnaby wrote:Of the 60 animals in the farm, 2/3 of the animals are either cows or pigs. How many of the animals are cows?

1) the farm has more than twice as many cows as it has pigs

2) the farm has more than 12 pigs

Pls explain
If 2/3 of the 60 animals are cows or pigs, then 60 * (2/3) = 40 are cows or pigs. So Cows + Pigs = 40.

Statement 1:There could be 39 cows and 1 pig or 38 cows and 2 pigs, etc. Not sufficient.

Statement 2: there could be 13 pigs and 27 cows, there could be 14 pigs and 26 cows, etc. Not sufficient.

Together. We've got three pieces: 1) cows and pigs sum to 40; 2)there are more than twice as many cows as pigs; 3) there are more than 12 pigs
The only scenario that will satisfy all three: 27 cows and 13 pigs. (If there were 26 cows and 14 pigs, there wouldn't be more than twice as many cows. If there were 28 cows and 12 pigs, there wouldn't be more than 12 pigs.) Because there is a unique value - 27 cows - together the statements are sufficient. Answer is C
Veritas Prep | GMAT Instructor

Veritas Prep Reviews
Save $100 off any live Veritas Prep GMAT Course
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members
Location: Vancouver, BC
Thanked: 5254 times
GMAT Score:770

by Brent@GMATPrepNow » Fri Jan 01, 2016 10:52 am
Of the 60 animals on a certain farm, 2/3 are either pigs or cows. How many of the animals are cows?
(1) The farm has more than twice as many cows as it has pigs.
(2) The farm has more than 12 pigs.
Target question: How many of the animals are cows?

Given: Of the 60 animals in a certain farm, 2/3 are either pigs or cows
Let P = # of pigs
Let C = # of cows
2/3 of 60 = 40, so we can say that P + C = 40

Statement 1: The farm has MORE THAN twice as many cows as it has pigs.
In other words, 2P < C
If we know 2P < C and P + C = 40, do we have sufficient information to find the value of C?
No. Consider these 2 conflicting cases:
Case a: P = 1 and C = 39, in which case there are 39 cows
Case b: P = 2 and C = 38, in which case there are 38 cows
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: The farm has more than 12 pigs.
There's no way we can use this information to determine the number of cows.
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Statement 2 says that P > 12. So, let's examine some possibilities.
If P = 13, then C > 26 (from statement 1). So, C must equal 27 (since P + C = 40)
If P = 14, then C > 28 (from statement 1). In this case, P+C will be GREATER THAN 40, but we need P+C to EQUAL 40 (from the given information). So, P cannot equal 14.
In fact, for the same reasons, P cannot equal 15, 16, 17, etc. . .

So, the only case that's possible is for there to be 13 pigs and 27 cows
Since we can now answer the target question with certainty, the combined statements are SUFFICIENT

Answer = C

Cheers,
Brent
Last edited by Brent@GMATPrepNow on Mon Jan 25, 2016 10:43 am, edited 1 time in total.
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 313
Joined: Tue Oct 13, 2015 7:01 am
Thanked: 2 times

by jain2016 » Mon Jan 25, 2016 9:23 am
2/3 of 60 = 40, so we can say that P + C = 40

Hi Brent ,

Just a quick question. why can we say that P+c=40?

We have only given either P = 2/3*60 or C=2/3*60 right?

Please explain and correct me if took in other way.

Many thanks in advance.

SJ
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members
Location: Vancouver, BC
Thanked: 5254 times
GMAT Score:770

by Brent@GMATPrepNow » Mon Jan 25, 2016 10:46 am
jain2016 wrote:
2/3 of 60 = 40, so we can say that P + C = 40

Hi Brent ,

Just a quick question. why can we say that P+c=40?

We have only given either P = 2/3*60 or C=2/3*60 right?

Please explain and correct me if took in other way.

Many thanks in advance.

SJ
If P = # of pigs and C = # of cows, then P + C = total number of pigs and cows.
Since 40 of the animals (2/3 of 60) are either pigs or cows, we can conclude that P + C = 40

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 416
Joined: Thu Oct 15, 2009 11:52 am
Thanked: 27 times

by regor60 » Mon Jan 25, 2016 11:27 am
jain2016 wrote: We have only given either P = 2/3*60 or C=2/3*60 right?

SJ
No. That would be written "either the cows or the pigs are 2/3"

The intention of the wording is that a group of 40 animals (2/3x60) is made up of both cows and pigs
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 313
Joined: Tue Oct 13, 2015 7:01 am
Thanked: 2 times

by jain2016 » Mon Jan 25, 2016 10:12 pm
Brent@GMATPrepNow wrote:
jain2016 wrote:
2/3 of 60 = 40, so we can say that P + C = 40

Hi Brent ,

Just a quick question. why can we say that P+c=40?

We have only given either P = 2/3*60 or C=2/3*60 right?

Please explain and correct me if took in other way.

Many thanks in advance.

SJ
If P = # of pigs and C = # of cows, then P + C = total number of pigs and cows.
Since 40 of the animals (2/3 of 60) are either pigs or cows, we can conclude that P + C = 40

Cheers,
Brent
Hi Brent,

Thanks for your reply.

So what I understood is that, here, "either the cows or the pigs are 2/3" means P+C=40 right?

Please advise.

Thanks,

SJ
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1