Given that there are three couples, who are to be arranged in 6 seats. Find how many ways they can be arranged, such that husband and wife sit together?
Let AB, PQ and XY be the three couples.
These 3 couples can be arranged in 3! ways.
Each couple can seat themselves in 2! ways in the two chairs allotted to them.
Hence, 3! * 2! * 2! * 2! = 48 ways.
By the way, is this an 'arrangement' question or a 'probability' question ?
If it is a probability question,
P(the event above) = 48 / 6!.
Hope this helps. Thanks.
