K is a multiple of 11. So K = 11n, where n is a positive integer.
Is KL a multiple of 154? .... 154 = 11 * 14 = 11 * 7 * 2
Thus for an answer of yes we would need the product KL to contain all 3 primes - 11, 7 and 2.
STATEMENT 1:
L has all the same factors as 42. This is a flowery way of saying that L is a multiple of 42.
42 = 2 * 7 * 3
So L = 2 * 7 * 3 * m .... where m is a positive integer.
=> K * L = 11* n * 2* 7*3*m => we have all 3 primes 11, 7 and 2 in this --- SUFFICIENT
STATEMENT 2:
K is divisible by 21.
21 = 7 * 3
This means K must contain atleast one each of 7 and 3 in order that it is divisible by 21.
-> K = 11 * 7 * 3 * p ... where p is some positive integer.
But we do not know anything about L. So we cannot be sure if we are going to get that 2 we want to or not.
INSUFFICIENT
Pick A.
~Abhay
Believe those who are seeking the truth. Doubt those who find it. -- Andre Gide
