I sort of got the answer...but my method was somewhat crude...maybe some one has a better answer for you.

First I figured out the x and y intercepts of the line. (4,0) and (-3,0). this told me right away that there is some sort of a 3-4-5 triangle involved with it.

you know the radius of the circle is 1 with origin at (0,0).

when you draw it out in paper, you would have a right triangle in the 4th quadrant with 1/4 of the circle coming in the way.

The shortest distance would be the line perpendicular to the line Y=3/4X-3 and the circle.

so what I did was draw out a rectangle at the 4th quadrant (basically two 3-4-5 triangles) (0,0)(4,0)(-3,0)(4,-3)

Then I drew two diagonals with the length of 5 within the rectangle. The distance from the origin(0,0) to the midpoint of the rectangle is approximately 2.5.

the radius is 1, so you subtract 2.5 from 1 to get ~1.5 which is closest to A.

Like I said, my method was crude and I am not even sure if it right...maybe someone has a better explanation.

perpendicular Distance(shortest distance) of a point (x1,y1) from a line ax+by+c = 0 is given by
d = |(a*x1)+(b*y1)+c|/(a^2+b^2)^1/2

Let us calculate the distance of the line from the center of the circle (0,0)
a = -3/4
b=1
c=3
x1=0
y1=0

therefore d= 12/5

distance from a point on the circle would be 12/5-1 = 1.4

hope this helps!!

ssmiles08 wrote:
the radius is 1, so you subtract 2.5 from 1 to get ~1.5 which is closest to A.

one thing to note here in this question is two answer choices are pretty close

A) 1.4 and B) (2) ^1/2 ~ 1.414

if we bring down the calculation to ~1.5 , either A or B could be the answer..

Claret wrote:

ssmiles08 wrote:
the radius is 1, so you subtract 2.5 from 1 to get ~1.5 which is closest to A.

one thing to note here in this question is two answer choices are pretty close

A) 1.4 and B) (2) ^1/2 ~ 1.414

if we bring down the calculation to ~1.5 , either A or B could be the answer..

Yes you are right. Thank you.

O_O ...this is a possible GMAT problem?

I don't even know where to start. What does "circle x^2 + y^2 = 1" even mean??

sanju, Ian, Kowinsky, please comment, found it very difficult for gmat

The answer is indeed 1.4 but I think it needs to be solved differently.

I think everybody has figured out the vertices of traingle OAB that is O (0,0), A(0,-3) and B(4,0). Now draw a perpendicular line from O to AB (Sorry I have not drawn fig). Say it touches OB at D.

Now you can find out OD= OB*Sin <OAB

= 4*3/5
= 12/5

We know that a tangent on any point on the circle is perpendicular to the radius.

Therefore, the shortest distance from any point on circle to the line AB= OD- Radius of the circle

i.e. 12/5-1= 1.4