theCodeToGMAT wrote:Five pieces of wood have an average (arithmetic mean) length of 124 centimeters and a median length of 140 centimeters. What is the maximum possible length, in centimeters, of the shortest piece of wood?
a)60
b)80
c)100
d)120
e)140
Let the pieces be arranged in ascending Order of their Length as follows -
A , B , C , D , E
Or , A > B > C > D > E
Arithmetic mean length of 124.
Length of all the pieces is 124*5 = 620 cm
So A + B + C + D + E = 620
Now the part " median length of 140 centimeters " means its the value below which 50% of the cases fall.
Here 50% of the 5 pieces will be 3.
So , A > B > 140 > 140 > 140
So we have A + B + 420 = 620
Hence A + B = 200
Now it boils down to A + B is 200 and we simply require to maximize A.
Keep Checking the options -
a. A = 60 , then B = 40
[ Can be maximized further ]
b. A = 80 , then B = 20
[ Can be maximized further ]
c. A = 100 , then B = 100
Can not be maximized further
d . A = 120 , then B = 80
Not possible because here A becomes more than B and violates our condition of arrangement of the pieces as A > B > C > D > E
e. A = 140 , then B = 60
Not possible because here A becomes more than B and violates our condition of arrangement of the pieces as A > B > C > D > E
Hope this helps...