x,y, and z are integers, is x even?
(1) 1O^x = (4^x)(5^z)
(2) 3^(x+5) = 27^(y+1)
Please Help.
Thanks.
GGK.
(1) 1O^x = (4^x)(5^z)
(2) 3^(x+5) = 27^(y+1)
Please Help.
Thanks.
GGK.
There's something wrong with the question - where is it from? Either it's badly designed, or Statement 1 is meant to read something more like: 10^x = (4^z)(5^x).
As written, it's impossible for both statements to be true. From Statement 1 we have:
2^x * 5^x = 2^(2x) * 5^z
Our exponents are integers, so they need to be the same on both sides of this equation. So, looking at the powers on the 2s on the left and right sides, x = 2x must be true, and the only possibility is that x=0. So Statement 1 is sufficient.
But if you look at Statement 2, x cannot be 0, so that makes the two statements inconsistent, which is why the question is either flawed or incorrectly transcribed. In any case, Statement 2 is not sufficient; we find that
3^(x+5) = 3^(3y + 3)
so x+5 = 3y+3, and x = 3y -2. Since 3y-2 might be even or might be odd, we don't know if x is even.
my typo mistake.
