BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

At a certain school, the ratio of the number of second grad

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 124
Joined: Wed May 19, 2010 10:20 pm
Thanked: 3 times
GMAT Score:1100
by mitzwillrockgmat » Sat Jun 05, 2010 10:06 am
At a certain school, the ratio of the number of second
graders to the number of fourth graders is 8 to 5, and
the ratio of the number of first graders to the number of
second graders is 3 to 4. If the ratio of the number of
third graders to the number of fourth graders is 3 to 2 ,
what is the ratio of the number of first graders to the
number of third graders?

a. 16 to 15
b. 9 to 5
c. 5 to 16
d. 5 to 4
e. 4 to 5

Hi, I want to know how i can do this question faster?
I can solve it but i take almost 2 minutes!!
any shortcuts for these types of questions?

2nd /4th = 8/5
1st /2nd = 3/4
3rd/4th =3/2

find 1st/3rd =?

3rd/4th = 3/2 * 5/5 = 15/10

2nd /4th = 8/5 * 2/2 = 16/10

1st /2nd = 3/4 *4/4 = 12/16

so 1st/3rd = 12/15 = 4/5

but how can i do this faster? including reading time im touching almost 2.5 minutes!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Master | Next Rank: 500 Posts
Posts: 161
Joined: Mon Apr 05, 2010 9:06 am
Location: Mumbai
Thanked: 37 times

by 4GMAT_Mumbai » Sat Jun 05, 2010 10:29 am
After 1st sentence, in one's mind,

1st:2nd:4th = 6:8:5

3rd:4th = 3:2

To match 1st and 2nd equations, multiply 1st eq by 2 and 2nd eq by 5

1st:2nd:3rd:4th = 12:16:15:10

From this, 1st:3rd = 12:15 = 4:5

Hope this helps. Thanks.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 124
Joined: Wed May 19, 2010 10:20 pm
Thanked: 3 times
GMAT Score:1100

by mitzwillrockgmat » Sat Jun 05, 2010 12:33 pm
4GMAT_Mumbai wrote:After 1st sentence, in one's mind,

1st:2nd:4th = 6:8:5 *******the 6 is a mistake right? should be 3:8:5 no?

3rd:4th = 3:2

To match 1st and 2nd equations, multiply 1st eq by 2 and 2nd eq by 5

1st:2nd:3rd:4th = 12:16:15:10

From this, 1st:3rd = 12:15 = 4:5

Hope this helps. Thanks.
Thanks! this is faster than what i was doing!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 56
Joined: Fri Mar 05, 2010 9:50 pm
Thanked: 1 times

by muralithe1 » Sun Jun 06, 2010 11:56 am
Hi,
This is my apporach..

2nd /4th = 8/5
1st /2nd = 3/4
3rd/4th =3/2


2nd/4th * 1st/2nd * 4th/3rd = 1st/3rd= 8/5*3/4*2/3= 4/5
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 124
Joined: Wed May 19, 2010 10:20 pm
Thanked: 3 times
GMAT Score:1100

by mitzwillrockgmat » Sun Jun 06, 2010 12:56 pm
muralithe1 wrote:Hi,
This is my apporach..

2nd /4th = 8/5
1st /2nd = 3/4
3rd/4th =3/2


2nd/4th * 1st/2nd * 4th/3rd = 1st/3rd= 8/5*3/4*2/3= 4/5
Hi, this works!!! but im not sure if there's an actual mathematical concept here or that the answer is just a coincidence i.e. that all given ratio's product is the answer. can you explain why & how you knew that multiplying all the given ratios would give the ratio that is being asked?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 56
Joined: Fri Mar 05, 2010 9:50 pm
Thanked: 1 times

by muralithe1 » Sun Jun 06, 2010 1:25 pm
No its not coincidence...


Then the ratios as as A/B * B/C * C/D = A/D


here ofcouce we have given D/C ratio, so for our convenience while we multiply.. i inverted to C/D...so when i multiply...


Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Newbie | Next Rank: 10 Posts
Posts: 5
Joined: Mon Jun 07, 2010 10:15 am
GMAT Score:710

by nmerchant » Tue Jun 08, 2010 12:12 pm
muralithe1 wrote:Hi,
This is my apporach..

2nd /4th = 8/5
1st /2nd = 3/4
3rd/4th =3/2


2nd/4th * 1st/2nd * 4th/3rd = 1st/3rd= 8/5*3/4*2/3= 4/5
Yup.. I did the same thing.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Junior | Next Rank: 30 Posts
Posts: 17
Joined: Mon May 17, 2010 8:16 pm
Location: Indonesia
GMAT Score:340

by eloka » Tue Jun 08, 2010 5:27 pm
Okay...this is my approach..eloka's way

x = 2nd grade
y= 4th grade
m= 1st grade
k= 3rd grade

x:y = 8:5 (*2) ===> x:y = 16:10======> x:y = 16:10
m:x=3:4 (*2)====> m : x = 6: 8 (*2) ==> m :x = 12: 16
k:y = 3:2(*5)====> k:y = 15:10======> k:y = 15:10

Now we know x and y are equal to all the ration. Therefore, we can find the ratio solution for m:k = 12: 15 = 4:5
m/k = 4/5
Warm wishes to all of you who are striving to conquer the GMAT

Eloka
Indonesia
https://lavachoco.blocked
All I need is 450 GMAT score!! thats all, Geez
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Junior | Next Rank: 30 Posts
Posts: 17
Joined: Mon May 17, 2010 8:16 pm
Location: Indonesia
GMAT Score:340

by eloka » Tue Jun 08, 2010 5:31 pm
Okay...this is my approach..eloka's way

x = 2nd grade
y= 4th grade
m= 1st grade
k= 3rd grade

x:y = 8:5 multiply with (*2) ===> x:y = 16:10======> x:y = 16:10
m=3: 4 multiply with (*2)====> m : x = 6: 8 multiply again with (*2) ==> m = 12: 16
k:y = 3: 2 multiply with (*5)====> k:y = 15:10======> k:y = 15:10

keep multiplying until you find x and y in a ratio group shares the same number. As you can see

x/y = 16/10
m/x = 12/16
k/y=15/10

x is 16 and y is 10....so now we can find ratio of m to k


Now we know x and y are equal to all the ration. Therefore, we can find the ratio solution for m:k = 12: 15 = 4:5
m/k = 4/5
Warm wishes to all of you who are striving to conquer the GMAT

Eloka
Indonesia
https://lavachoco.blocked
All I need is 450 GMAT score!! thats all, Geez
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1