mathewmithun wrote:If x + y^2= ( x + y ^2) ^2, what is the value of y?
( 1) x = y ^2
( 2) xy ^2 = 0
I feel E is the answer but some can help me to cross verify...
If x + y^2 = (x + y ^2) ^2, then
x + y^2 = x^2 + 2 x y^2 + y ^4
(1) When x = y ^2, x + y^2 = x^2 + 2 x y^2 + y ^4 becomes
y^2 + y^2 = y^4 + 2 y^4 + y ^4, or
2 y^2 = 5 y^4
It's a 4-degree in y, no unique y can be known. Insufficient
(2) When x y ^2 = 0, at least either x or y is 0; moreover we can have
x + y^2 = x^2 + y ^4
if x is 0, and y is not, we get 2 non zero values for y, otherwise y is 0. Insufficient
When taken together, we realize that [spoiler]
y is 0.
C[/spoiler]
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Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
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