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bellcurve
- Senior | Next Rank: 100 Posts
- Posts: 37
- Joined: Fri Jun 25, 2010 11:07 am
- Thanked: 1 times
I have a clearifying question about set theory formulas, if you all don't mind.
1. For 3 sets A, B, and C: P(AuBuC) = P(A) + P(B) + P(C) - P(AnB) - P(AnC) - P(BnC) + P(AnBnC)
2. No of persons in atleast one set = P(A) + P(B) + P(C) - P(AnB) - P(AnC) - P(BnC) + 2P(AnBnC)
Why these two formulas are different (+ P(AnBnC)in the first one vs 2P(AnBnC)in the second one)?
Isn't "at least in one set" equal to union of all (AuBuC)?
Thanks,
BC
1. For 3 sets A, B, and C: P(AuBuC) = P(A) + P(B) + P(C) - P(AnB) - P(AnC) - P(BnC) + P(AnBnC)
2. No of persons in atleast one set = P(A) + P(B) + P(C) - P(AnB) - P(AnC) - P(BnC) + 2P(AnBnC)
Why these two formulas are different (+ P(AnBnC)in the first one vs 2P(AnBnC)in the second one)?
Isn't "at least in one set" equal to union of all (AuBuC)?
Thanks,
BC

















