Probability

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SwatiDenre: Junior | Next Rank: 30 Posts; Posts: 13; Joined: Mon Apr 18, 2011 4:34 pm

Probability

by SwatiDenre » Mon Jun 13, 2011 5:16 pm

How many 5 digit numbers can be formed using the digits 0,2,3,4and5 when repetition is allowed such that the number formed is divisible by 2 or 5 or both?

A. 100
B. 125
C. 3125
D. 1500
E. 125

Ans- 1500

Solution?
Thanks in advance.

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Source: Beat The GMAT — Problem Solving | Mon Jun 13, 2011 5:16 pm

MBA.Aspirant: Master | Next Rank: 500 Posts; Posts: 401; Joined: Tue May 24, 2011 1:14 am; Thanked: 37 times; Followed by:5 members

by MBA.Aspirant » Mon Jun 13, 2011 6:41 pm

I'm getting 2000 for this one!?

1st digit can be decided in 4 ways (2,3,4,5)
2nd in 5 ways (0,2,3,4,5)
3rd 5 ways
4th 5 ways
5th 4 ways to be divisible by 2 or 5 or both (0,2,4,5)

4*5*5*5*4 = 2000 ways

Quote

Ashley@VeritasPrep: GMAT Instructor; Posts: 199; Joined: Tue May 17, 2011 6:06 am; Location: Cambridge, MA; Thanked: 192 times; Followed by:121 members; GMAT Score:780

by Ashley@VeritasPrep » Mon Jun 13, 2011 7:14 pm

Me too... please verify the problem! And do you trust the source to be without error, if this is indeed what the problem says?

Thanks!

Ashley Newman-Owens
GMAT Instructor
Veritas Prep

Post helpful? Mosey your cursor on over to that Thank button and click, please! I will bake you an imaginary cake.