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by [email protected] » Wed Jun 08, 2011 3:08 am
A man traveled a distance of 80 km in 7 hrs partly on foot at the rate of 8 km. per hour and partly on bicycle at 16km. per hour. Find the distance traveled on food.

A] 36
B]42
C]32
D] 56
E] 28

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by cans » Wed Jun 08, 2011 3:15 am
let x be distance traveled on foot. thus 80-x on bicycle
Time taken by foot distance = x/8
time taken by bicycle distance = (80-x)/16 = 5 - x/16
total time = x/8 + 5 - x/16 = 7
x/16 = 2
x=32
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by manpsingh87 » Wed Jun 08, 2011 3:37 am
[email protected] wrote:A man traveled a distance of 80 km in 7 hrs partly on foot at the rate of 8 km. per hour and partly on bicycle at 16km. per hour. Find the distance traveled on food.

A] 36
B]42
C]32
D] 56
E] 28

OA later,,,
let p be the no. of hours for which a man traveled on foot and q be the no. of hours for which man traveled on bicycle.

so distance traveled on foot=8p;
also 8p+16q=80;----1)
and p+q=7;----2)
multiply 2 with 16 we have;
16p+16q=112;
now subtract 1 from the above equation we have
8p=32;
hence c[spoiler][/spoiler]
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by khound.siddharth » Wed Jun 08, 2011 5:17 am
Such questions are best ans by taking the options and working with them to get the soln.
Start with the middle value and then work out. If the tried value is less than go for the nxt higher figure...if low then take the next lower value.
Here if I start with option c for instance -
32 kmps / 8 = 4 hts
remaining kms -> 48/16 = 3 hrs
4+3 = 7 hrs...just what the question said - the person coverd 80 kms in 7 hrs.

My 2 cents.
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by khound.siddharth » Wed Jun 08, 2011 5:19 am
Such questions are best ans by taking the options and working with them to get the soln.
Start with the middle value and then work out. If the tried value is less than go for the nxt higher figure...if low then take the next lower value.
Here if I start with option c for instance -
32 kmps / 8 = 4 hts
remaining kms -> 48/16 = 3 hrs
4+3 = 7 hrs...just what the question said - the person coverd 80 kms in 7 hrs.

My 2 cents.
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by [email protected] » Wed Jun 08, 2011 6:12 am
Thank you guyz for helping me. It was not difficult but rather chicky....
IT IS TIME TO BEAT THE GMAT

LEARNING, APPLICATION AND TIMING IS THE FACT OF GMAT AND LIFE AS WELL... KEEP PLAYING!!!

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by iamsaurav » Wed Jun 08, 2011 7:24 am
khound.siddharth wrote:Such questions are best ans by taking the options and working with them to get the soln.
Start with the middle value and then work out. If the tried value is less than go for the nxt higher figure...if low then take the next lower value.
Here if I start with option c for instance -
32 kmps / 8 = 4 hts
remaining kms -> 48/16 = 3 hrs
4+3 = 7 hrs...just what the question said - the person coverd 80 kms in 7 hrs.

My 2 cents.
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by finites » Wed Jun 08, 2011 11:55 am
16x + 8y = 80

x + y =7

x + x + y = 10

x + 7 = 10
x = 3
y = 4

8y = 32
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by rarns » Wed Jun 08, 2011 12:35 pm
What I found easiest:

80 = 8x + 16y

7 = x + y, hence: x = 7 - y

Plug in: 80 = 8(7-y) + 16y
24 = 8y
3 = y,

So, x = 4, & 8(4) = 32
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