BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

PDF800 SET1 question 18

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 56
Joined: Tue Feb 13, 2007 6:19 am
by zozo123 » Tue Jul 31, 2007 2:30 am
On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?

A. 33 1/3%
B. 40%
C. 50%
D. 60%
E. 66 2/3%
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Newbie | Next Rank: 10 Posts
Posts: 2
Joined: Sat Jul 28, 2007 9:52 am

by trandb » Tue Jul 31, 2007 5:59 am
is C (50 %) the answer ?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 27
Joined: Mon Mar 19, 2007 6:23 pm
Location: Cambridge, MA

by mindruna » Tue Jul 31, 2007 7:45 am
I would also say 50%.

The 20% of the (total) passengers hold a round trip ticket and have cars and 60% of round trip passengers have no cars. You can see that the 20% is equal to 40% of the total passengers and that means that those with round trip tickets without cars are equal to 30% of the total passengers.


30% +20%=50%
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 33
Joined: Thu Jul 05, 2007 1:28 pm

by lalitgmat » Tue Jul 31, 2007 8:58 am
If you combine all AND clauses,
1> 20% of Ships's passengers (SP) have CAR aboard.
2> 60% of SP DO NOT have CAR aboard.
Now my argue is "how are you sure that ship does NOT have any other type of passenger". Basically how you deduce that "ALL passengers of ship have round-trip tickets".
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 27
Joined: Mon Mar 19, 2007 6:23 pm
Location: Cambridge, MA

by mindruna » Tue Jul 31, 2007 9:02 am
I feel like you have to assume that there are no other types of passengers other than those with and without a car and those with and without round trip tickets. If not, there would be no way to solve the problem...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 986
Joined: Wed Dec 20, 2006 11:07 amFollowed by: 1 member
Location: India
Thanked: 51 times

by gabriel » Tue Jul 31, 2007 9:16 am
... guyz .. seriously ignore this question .. the construction of the question leaves a lot of room for ambiguity ..
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1