If the length and width of rectangle R are each increased by 1, the area of the new rectangle will be 72. If the length

This topic has expert replies
Moderator
Posts: 2599
Joined: Sun Oct 29, 2017 2:08 pm
Followed by:2 members

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

Magoosh

If the length and width of rectangle R are each increased by 1, the area of the new rectangle will be 72. If the length and width of rectangle R are each decreased by 1, the area of the new rectangle will be 35. What is the perimeter of rectangle R?

A. 34
B. 37
C. 48
D. 50
E. 51

OA B
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770
AAPL wrote:
Mon Jun 28, 2021 8:50 am
Magoosh

If the length and width of rectangle R are each increased by 1, the area of the new rectangle will be 72. If the length and width of rectangle R are each decreased by 1, the area of the new rectangle will be 35. What is the perimeter of rectangle R?

A. 34
B. 37
C. 48
D. 50
E. 51

OA B
Let L = the length of rectangle R
Let W = the width of rectangle R

If the length and width of rectangle R are each increased by 1, the area of the new rectangle will be 72.
We can write: (L + 1)(W + 1) = 72
Expand to get: LW + L + W + 1 = 72

If the length and width of rectangle R are each decreased by 1, the area of the new rectangle will be 35.
We can write: (L - 1)(W - 1) = 35
Expand to get: LW - L - W + 1 = 35

What is the perimeter of rectangle R?
The perimeter = L + W + L + W = 2L + 2W

So far we have:
LW + L + W + 1 = 72
LW - L - W + 1 = 35

When we subtract the bottom equation from the top equation we get: 2L + 2W = 37
Since the perimeter = 2L + 2W, we can see that the correct answer is B
Brent Hanneson - Creator of GMATPrepNow.com
Image