A. 2p>7 ==>p>3.5 possible
B. 3p<7 ==>p<2(1/3) >2 possible
C. P<3 ==> p can be 2.5>2, possible
D. P>4 possible as p can be anything as along it is >2
E. 3p<6 ==>p<2 which is contradicts p>2
hence E
P>2
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Source: Beat The GMAT — Problem Solving |
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scoobydooby
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