Profit/loss

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Profit/loss

by Joy Shaha » Sat Jul 09, 2016 1:46 pm
Q. Jennifer can buy watches at a price of B dollars per watch, which she marks up by a certain percentage before selling. If she makes a total profit of T by selling N watches, then in terms of B and T and N, what is the percent of the markup from her buy price to her sell price?

(A) 100T/(NB)
(B) TB/(100N)
(C) 100TN/B
(D) ((T/N) - B)/(100B)
(E) 100(T - NB)/N
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by GMATGuruNY » Sun Jul 10, 2016 2:02 am
Joy Shaha wrote:Q. Jennifer can buy watches at a price of B dollars per watch, which she marks up by a certain percentage before selling. If she makes a total profit of T by selling N watches, then in terms of B and T and N, what is the percent of the markup from her buy price to her sell price?

(A) 100T/(NB)
(B) TB/(100N)
(C) 100TN/B
(D) ((T/N) - B)/(100B)
(E) 100(T - NB)/N
Let:
B = $50 per watch.
N = 2 watches.
T = $10 total profit.

Since 2 watches together earn a total profit of $10, the profit per watch = $5.
Thus:
(profit per watch)/(cost per watch) = 5/50 = 1/10 = 10%. This is our target.

Now plug B=50, N=2 and T=10 into the answers to see which yields our target of 10.
Only A works:
100T/NB = (100*10)/(2*50) = 10.

The correct answer is A.
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by OptimusPrep » Sun Jul 10, 2016 8:16 pm
Joy Shaha wrote:Q. Jennifer can buy watches at a price of B dollars per watch, which she marks up by a certain percentage before selling. If she makes a total profit of T by selling N watches, then in terms of B and T and N, what is the percent of the markup from her buy price to her sell price?

(A) 100T/(NB)
(B) TB/(100N)
(C) 100TN/B
(D) ((T/N) - B)/(100B)
(E) 100(T - NB)/N
Cost price of one watch = B
Cost price of N watches = B*N

Total profit on N watches = T

Markup percentage = Profit/Cost Price *100 = T/BN * 100 = 100T/BN

Correct Option: A