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Minimum possible population of least populated district

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Minimum possible population of least populated district

by DevB » Mon Jun 16, 2014 10:10 am
Hi Everyone,

Please help me in answering the below question from GMATPrep:

A certain city with a population of 132,000 is to be divided into 11 districts, and no district is to have a population that is more than 10 percent greater than the population of any other district. What is the minimum possible population that the least populated district could have?

1. 10,700
2. 10,800
3. 10,900
4. 11,000
5. 11,100

Please explain the solution also.

Many Thanks!!
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by GMATGuruNY » Mon Jun 16, 2014 10:48 am
A certain city with a population of 132,000 is to be divided into 11 voting districts and no district is to have a population that is more than 10% greater than the population of any other district. what is the minimum possible population that the least populated district could have?
a) 10,700
b) 10,800
c) 10,900
d) 11,000
e) 11,100
We can plug in the answer choices, which represent the minimum possible population of the least populated district.

To MINIMIZE the smallest population, we need to MAXIMIZE the other 10 populations.
Thus, each of the other 10 districts must have the maximum allowed population: 10% greater than the smallest population.
Since the total population of the city is 132,000 -- a multiple of 1,000 -- the correct answer choice is almost certainly a multiple of 1,000.

Answer choice D: Least populated district = 11,000.
Maximum value of each of the other 10 districts = 11,000 + .1(11,000) = 12,100.
Sum of the 11 districts = 11,000 + 10(12,100) = 132,000.
Success!

The correct answer is D.

Algebraically:
Let x = the population of the least populated district.
As noted above, to MINIMIZE the smallest population, we need to MAXIMIZE the other 10 populations.
Thus, each of the other 10 districts must have the maximum allowed population:
10% greater than the smallest population = 1.1x.
Thus, the sum of the populations in the other 10 districts = 10(1.1x) = 11x.
Since the sum of ALL the populations is equal to 132,000, we get:
x + 11x = 132,000
12x = 132,000
x = 11,000.
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by DevB » Mon Jun 16, 2014 11:00 am
Thank you Mitch for your quick replies and detailed explanations...!!

Answer is correct :)
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by tass@ » Mon Jun 16, 2014 12:36 pm
let the least number is "x"
Now there are 10 numbers left which are (x+.10x)
So total sum of 10 numbers will be 10(1.1x)=11x
Now x+11x = 132000
x= 11000
So this is the answer
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