each item costs $8.
Total number of items = n
total cost = 8n
cost for postage:
1st item = $3
remaing at $1 each
remaining items = n-1
total postage = 3 + n - 1 = n +2
total cost = 8n + (n + 2) = 9n + 2
n items purchased
This topic has expert replies
Source: Beat The GMAT — Problem Solving |
-
Travis_1234567890
- Senior | Next Rank: 100 Posts
- Posts: 30
- Joined: Mon Jul 07, 2008 3:38 pm
- Location: Atlanta
- Thanked: 6 times
Alternatively, you could plug in numbers….
Let n = 2 (any number will work)
$8 * n = 8 * 2 = 16 (price before postage and handling)
3$ (postage/handling for the first item)
1$ (postage/handling for the second item)
16 + 3 + 1 = 20 (Total price including shipping)
Now, plug in the “2” in each answer….
C) 9n + 2 = (9*2) + 2 = 20
Let n = 2 (any number will work)
$8 * n = 8 * 2 = 16 (price before postage and handling)
3$ (postage/handling for the first item)
1$ (postage/handling for the second item)
16 + 3 + 1 = 20 (Total price including shipping)
Now, plug in the “2” in each answer….
C) 9n + 2 = (9*2) + 2 = 20












